Which of the following complex ions will have | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.82 \ BM$,$n$ mus

Vedclass · Accepted Answer

$[NiCl_4]^{2-}$

Vedclass · Answer

(B) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.82 \ BM$,$n$ must be $2$.In $Ni(CO)_4$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons,resulting in $n=0$.In $[NiCl_4]^{2-}$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $Cl^-$ is a weak field ligand,so electrons do not pair up,resulting in $n=2$.In $Ni(PPh_3)_4$,$Ni$ is in $0$ oxidation state,resulting in $n=0$.In $[Ni(CN)_4]^{2-}$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $n=0$.Thus,$[NiCl_4]^{2-}$ has $2$ unpaired electrons and a magnetic moment of $2.82 \ BM$.

Which of the following complex ions will have a magnetic moment of $2.82 \ BM$?

Similar Questions

Which of the following complexes is colorless?

The existence of two different coloured complexes with the composition of $[Co(NH_3)_4Cl_2]^+$ is due to

Which among the following elements in their respective oxidation states develops the lowest spin-only magnetic moment? (Atomic numbers: $Cu=29, Fe=26, Ni=28, Co=27$)

Arrange the following in the increasing order of their magnetic moments:
$I.$ $[Mn(CN)_6]^{3-}$
$II.$ $[MnCl_6]^{3-}$
$III.$ $[Fe(CN)_6]^{3-}$
$IV.$ $[FeF_6]^{3-}$

The most paramagnetic complex is

Vedclass Test Series

Exam Paper Generator

Online Exam Module