Identify '$X$' and '$Y$' in the following sequence of transformations: $CH_3-CH_2-CH_2Br$ $\xrightarrow{X} \text{Product}$ $\xrightarrow{Y} CH_3-CH(Br)-CH_3$.

  • A
    $X = \text{dilute aqueous } NaOH, 20 \ ^\circ C, Y = HBr / \text{acetic acid } 20 \ ^\circ C$
  • B
    $X = \text{concentrated alcoholic } NaOH, 80 \ ^\circ C, Y = HBr / \text{acetic acid } 20 \ ^\circ C$
  • C
    $X = \text{dilute aqueous } NaOH, 20 \ ^\circ C, Y = Br_2 / CHCl_3, 0 \ ^\circ C$
  • D
    $X = \text{concentrated alcoholic } NaOH, 80 \ ^\circ C, Y = Br_2 / CHCl_3, 0 \ ^\circ C$

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Arrange the following halides in decreasing order of $S_N1$ reactivity:
$(I)$ $CH_3CH_2CH_2Cl$
$(II)$ $CH_2=CHCHClCH_3$
$(III)$ $CH_3CH_2CHClCH_3$

The main product of the following reaction will be:

What is the product $(A)$ in the following reaction?

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Which of the following represents the correct order of density?

Which of the following species is most reactive in $S_{N}2$ reaction?

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