The main product of the following reaction wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is a dehydrohalogenation of an alkyl halide using alcoholic $KOH$ (an elimination reaction,specifically $E2$ mechanism).The substrate

Vedclass · Accepted Answer

$Ph-CH_2-CH=C(CH_3)_2$

Vedclass · Answer

(A) The reaction is a dehydrohalogenation of an alkyl halide using alcoholic $KOH$ (an elimination reaction,specifically $E2$ mechanism).The substrate is $Ph-CH_2-CH(Cl)-CH(CH_3)_2$.Elimination occurs by removing the $Cl$ atom from the $\alpha$-carbon and a hydrogen atom from an adjacent $\beta$-carbon.There are two possible $\beta$-carbons:$1$. The $\beta$-carbon towards the phenyl group $(Ph-CH_2-)$: Removing $H$ from here gives $Ph-CH=CH-CH(CH_3)_2$.$2$. The $\beta$-carbon towards the isopropyl group (the $CH$ of the isopropyl group): Removing $H$ from here gives $Ph-CH_2-CH=C(CH_3)_2$.According to Zaitsev's rule,the more substituted alkene is the major product.$Ph-CH_2-CH=C(CH_3)_2$ is a trisubstituted alkene,while $Ph-CH=CH-CH(CH_3)_2$ is a disubstituted alkene.Therefore,$Ph-CH_2-CH=C(CH_3)_2$ is the major product.

The main product of the following reaction will be:

Similar Questions

An organic compound $A$ $(C_4H_9Cl)$ on reaction with $Na$/dry ether gives a hydrocarbon which on monochlorination gives only one chloro derivative. What is $A$?

Identify the major product $Y$ in the given reaction sequence.

The reactivity of $2-$bromo$-2-$methylbutane $(I)$,$1-$bromopentane $(II)$ and $2-$bromopentane $(III)$ towards $S_N2$ displacement is such that :

Which of the following reactions is used for the conversion of alkyl chloride to alkyl iodide?

The major product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module