The reactivity of 2-bromo-2-methylbutane (I), | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions involve the nucleophilic attac

Vedclass · Accepted Answer

$II > III > I$

Vedclass · Answer

(C) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions involve the nucleophilic attack from the back side,which is hindered by the presence of bulky groups around the electrophilic carbon.Therefore,the order of reactivity is $1^{\circ} > 2^{\circ} > 3^{\circ}$.In the given compounds:$1-$bromopentane $(II)$ is a primary $(1^{\circ})$ alkyl halide.$2-$bromopentane $(III)$ is a secondary $(2^{\circ})$ alkyl halide.$2-$bromo$-2-$methylbutane $(I)$ is a tertiary $(3^{\circ})$ alkyl halide.Thus,the correct order of reactivity towards $S_N2$ displacement is $II > III > I$.

The reactivity of $2-$bromo$-2-$methylbutane $(I)$,$1-$bromopentane $(II)$ and $2-$bromopentane $(III)$ towards $S_N2$ displacement is such that :

Similar Questions

Choose the correct decreasing order of reactivity of alkyl halides towards $S_{N}1$ reaction.

What is the product of the following $S_N2$ reaction?

Arrange the following compounds in order of decreasing rate of hydrolysis for $SN_1$ reaction:
$(I)$ $C_6H_5CH_2Br$
$(II)$ $p-CH_3-C_6H_4-CH_2Br$
$(III)$ $p-(CH_3)_2CH-C_6H_4-CH_2Br$
$(IV)$ $p-CH_3CH_2-C_6H_4-CH_2Br$

What is formed when $1$-bromo-$3$-chlorocyclobutane is treated with $2$ equivalents of sodium in ether?

What do you mean by dehydrohalogenation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module