The reaction of propene with $HOCl$ proceeds via the addition of which of the following in the first step?

  • A
    $H^{+}$ in the first step
  • B
    $Cl^{+}$ in the first step
  • C
    $OH^{-}$ in the first step
  • D
    $Cl^{+}$ and $OH^{-}$ in a single step

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$but-2-yne$ is reacted separately with one mole of $H_2$ as shown below:
$\underline{ B } \xleftarrow[\text{liq } NH_3]{Na} CH_3-C \equiv C-CH_3 \xrightarrow[\Delta]{Pd/C} \underline{ A }$
Identify the incorrect statements from the options given below:
$A.$ $A$ is more soluble than $B$.
$B.$ The boiling point and melting point of $A$ are higher and lower than $B$ respectively.
$C.$ $A$ is more polar than $B$ because dipole moment of $A$ is zero.
$D.$ $Br_2$ adds easily to $B$ than $A$.

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Which of the following reagents is used to prepare $Propan-1-ol$ from $propene$?

What is the major product expected from the following reaction?
Where $D$ is an isotope of hydrogen.

Addition of $HBr$ to propene yields $2$-bromopropane,while in the presence of benzoyl peroxide,the same reaction yields $1$-bromopropane. Explain and give mechanism.

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