When nitrobenzene is reacted with $Br_2$ in the presence of $FeBr_3$,the major product formed is $m$-bromonitrobenzene. This is because:

• A
  The electron density at the meta carbon is higher than at the ortho and para positions.
• B
  The meta position is the most stable site for the initial attack of $Br^+$ to form the intermediate carbocation.
• C
  The aromaticity is lost when $Br^+$ attacks the ortho,para,or meta positions.
• D
  The ortho and para positions lose $H^+$ more easily than the meta position to regain aromaticity.