What is the product formed when two molecules | vedclass

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(A) The addition of $HBr$ to propyne $(CH_3 - C \equiv CH)$ follows Markovnikov's rule.Step $1$: $CH_3 - C \equiv CH + HBr \rightarrow CH_3 - C(Br) =

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$CH_3 - CBr_2 - CH_3$

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(A) The addition of $HBr$ to propyne $(CH_3 - C \equiv CH)$ follows Markovnikov's rule.Step $1$: $CH_3 - C \equiv CH + HBr \rightarrow CH_3 - C(Br) = CH_2$ ($2$-bromopropene).Step $2$: $CH_3 - C(Br) = CH_2 + HBr \rightarrow CH_3 - C(Br)_2 - CH_3$ ($2$,$2$-dibromopropane).Thus,the final product is $CH_3 - CBr_2 - CH_3$.

What is the product formed when two molecules of $HBr$ are added to $CH_3 - C \equiv CH$?

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