Which of the following reactions will yield 2 | vedclass

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(A) The reaction of propyne $(CH_3-C \equiv CH)$ with two moles of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds t

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$CH_3-C \equiv CH + 2HBr \rightarrow$

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(A) The reaction of propyne $(CH_3-C \equiv CH)$ with two moles of hydrogen bromide $(HBr)$ follows Markovnikov's rule. In the first step,$HBr$ adds to the triple bond to form $2$-bromopropene $(CH_3-C(Br)=CH_2)$. In the second step,another molecule of $HBr$ adds to the double bond,again following Markovnikov's rule,to form $2,2$-dibromopropane $(CH_3-C(Br)_2-CH_3)$.

Which of the following reactions will yield $2,2$-dibromopropane as the product?

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