Tertiary alkyl halides are practically inert to $SN^2$ mechanism because of....

What is the product of this reaction?

The correct order for $E_2$ reaction with alc. $KOH$ will be

Which of the following statements is correct for optically active alkyl halides,upon reaction with nucleophiles?

	$S_{N}1$	$S_{N}2$
$(a)$	Retention of configuration	Inversion of configuration
$(b)$	Racemisation	Inversion of configuration
$(c)$	Inversion of configuration	Retention of configuration
$(d)$	Racemisation	Retention of configuration

Given below are two statements $:$
Statement $(I) :$ Alcohols are formed when alkyl chlorides are treated with aqueous potassium hydroxide by elimination reaction.
Statement $(II) :$ In alcoholic potassium hydroxide,alkyl chlorides form alkenes by abstracting the hydrogen from the $\beta-$carbon.
In the light of the above statements,choose the most appropriate answer from the options given below $:$

$CH_3Br + Nu^{-} \rightarrow CH_3-Nu + Br^{-}$
The decreasing order of the rate of the above reaction with nucleophiles $(Nu^{-})$ $A$ to $D$ is
$[Nu^{-} = (A) \, PhO^{-}, (B) \, AcO^{-}, (C) \, HO^{-}, (D) \, CH_3O^{-}]$