CH_3Br + Nu^{-} rightarrow CH_3-Nu + Br^{-}Th | vedclass

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Question

(C) The rate of the $S_N2$ reaction is directly proportional to the nucleophilicity of the attacking nucleophile.Nucleophilicity is inversely related

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$D > C > A > B$

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(C) The rate of the $S_N2$ reaction is directly proportional to the nucleophilicity of the attacking nucleophile.Nucleophilicity is inversely related to the strength of the corresponding conjugate acid.The order of acidity of the conjugate acids is: $CH_3COOH (AcOH) > C_6H_5OH (PhOH) > H_2O > CH_3OH$.Therefore,the order of basicity (nucleophilicity) is the reverse: $CH_3COO^{-} Thus,the decreasing order of the rate of reaction is: $D > C > A > B$.

$CH_3Br + Nu^{-} \rightarrow CH_3-Nu + Br^{-}$
The decreasing order of the rate of the above reaction with nucleophiles $(Nu^{-})$ $A$ to $D$ is
$[Nu^{-} = (A) \, PhO^{-}, (B) \, AcO^{-}, (C) \, HO^{-}, (D) \, CH_3O^{-}]$

Similar Questions

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$CH_3Br + Nu^{-} \rightarrow CH_3-Nu + Br^{-}$The decreasing order of the rate of the above reaction with nucleophiles $(Nu^{-})$ $A$ to $D$ is$[Nu^{-} = (A) \, PhO^{-}, (B) \, AcO^{-}, (C) \, HO^{-}, (D) \, CH_3O^{-}]$