Arrange the following compounds in decreasing order of their reactivity for hydrolysis reaction:
$(I)$ $C_6H_5-CH_2-Br$
$(II)$ $C_6H_5-CH(Br)-C_2H_5$
$(III)$ $CH_3-CH_2-Br$
$(IV)$ $C_6H_5-CH(Br)-C_6H_5$
$(I)$ $C_6H_5-CH_2-Br$
$(II)$ $C_6H_5-CH(Br)-C_2H_5$
$(III)$ $CH_3-CH_2-Br$
$(IV)$ $C_6H_5-CH(Br)-C_6H_5$
- A$I > II > III > IV$
- B$IV > II > I > III$
- C$III > IV > II > I$
- D$IV > III > II > I$
Explore More
Similar Questions
Chloroform reacts with concentrated $HNO_{3}$ to give
Difficult
View SolutionWhich of the following alkyl halides is the fastest to undergo dehydrohalogenation with a base?
Medium
View SolutionIn the given reaction,what is $A$?
$4-methylcyclohexyl bromide + OH^- \xrightarrow{S_N2} A$
$4-methylcyclohexyl bromide + OH^- \xrightarrow{S_N2} A$
Difficult
View SolutionArrange the following compounds in order of decreasing rate of hydrolysis for $SN_1$ reaction:
$(I)$ $C_6H_5CH_2Br$
$(II)$ $p-CH_3-C_6H_4-CH_2Br$
$(III)$ $p-(CH_3)_2CH-C_6H_4-CH_2Br$
$(IV)$ $p-CH_3CH_2-C_6H_4-CH_2Br$
$(I)$ $C_6H_5CH_2Br$
$(II)$ $p-CH_3-C_6H_4-CH_2Br$
$(III)$ $p-(CH_3)_2CH-C_6H_4-CH_2Br$
$(IV)$ $p-CH_3CH_2-C_6H_4-CH_2Br$
Difficult
View SolutionThe hydrolysis of optically active $2-$bromobutane with aqueous $NaOH$ results in the formation of:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo