In the structure CH_2 = CH - C equiv CH,what | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given structure is $CH_2 = CH - C \equiv CH$.Let us label the carbons as $C_1, C_2, C_3, C_4$ from left to right: $C_1H_2 = C_2H - C_3 \equiv

Vedclass · Accepted Answer

$sp^2, sp$

Vedclass · Answer

(A) The given structure is $CH_2 = CH - C \equiv CH$.Let us label the carbons as $C_1, C_2, C_3, C_4$ from left to right: $C_1H_2 = C_2H - C_3 \equiv C_4H$.The single bond is between $C_2$ and $C_3$.$C_2$ is bonded to one double bond and two single bonds (one with $C_1$,one with $H$,one with $C_3$),so it has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridization.$C_3$ is bonded to one triple bond and one single bond,so it has $2$ sigma bonds and $0$ lone pairs,resulting in $sp$ hybridization.Therefore,the hybridization states of the carbon atoms connected by the single bond are $sp^2$ and $sp$.

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

Similar Questions

The compound in which carbon uses only its $sp^3$ hybrid orbitals for bond formation is

How is the hybridization of carbon in an organic compound determined based on its structure? Explain.

The hybridization of carbon involved in the $C_2-C_3$ single bond in the molecule $CH \equiv C-CH=CH_2$ is

$1, 3$-butadiene has

The enolic form of acetone contains

Vedclass Test Series

Exam Paper Generator

Online Exam Module