Class 11Chemistry8-1.Organic Chemistry : Classification and Nomenclature of Organic compoundsBonding and hybridisation in organic compounds
MediumThe compound in which carbon uses only its $sp^3$ hybrid orbitals for bond formation is
- A$HCOOH$
- B$(NH_2)_2CO$
- C$(CH_3)_3COH$
- D$(CH_3)_3CHO$
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Similar Questions
In which of the following compounds is the underlined carbon atom $sp^3$ hybridized?
Easy
View SolutionExamine the following common chemical structures to which simple functional groups are often attached. Which of these systems have essentially planar geometry?
DifficultAIPMT 1995
View SolutionWhat are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$
Medium
View SolutionWhat is the hybridization state of carbon atoms $1, 2, 3,$ and $4$ in the given reaction?
Medium
View SolutionThe ascending acidity order of the following $H$ atoms is:
$A: HC \equiv C-H$
$B: H_2C=CH-H$
$C: (CH_3)_3C-H$
$D: CH_3-CH_2-H$
$A: HC \equiv C-H$
$B: H_2C=CH-H$
$C: (CH_3)_3C-H$
$D: CH_3-CH_2-H$
DifficultJEE MAIN 2024
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