Class 11Chemistry8-1.Organic Chemistry : Classification and Nomenclature of Organic compoundsBonding and hybridisation in organic compounds
MediumWhat are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$
(N/A) $(i)$ $CH_2=C=O$: The terminal $CH_2$ carbon is $sp^2$ hybridised,and the central $C$ is $sp$ hybridised.
$(ii)$ $CH_3-CH=CH_2$: The $CH_3$ carbon is $sp^3$ hybridised,while the $CH$ and $CH_2$ carbons are $sp^2$ hybridised.
$(iii)$ $(CH_3)_2CO$: Both $CH_3$ carbons are $sp^3$ hybridised,and the carbonyl $C=O$ carbon is $sp^2$ hybridised.
$(iv)$ $CH_2=CH-CN$: The $CH_2$ and $CH$ carbons are $sp^2$ hybridised,and the $CN$ carbon is $sp$ hybridised.
$(v)$ $C_6H_6$: All $6$ carbon atoms in the benzene ring are $sp^2$ hybridised.
$(ii)$ $CH_3-CH=CH_2$: The $CH_3$ carbon is $sp^3$ hybridised,while the $CH$ and $CH_2$ carbons are $sp^2$ hybridised.
$(iii)$ $(CH_3)_2CO$: Both $CH_3$ carbons are $sp^3$ hybridised,and the carbonyl $C=O$ carbon is $sp^2$ hybridised.
$(iv)$ $CH_2=CH-CN$: The $CH_2$ and $CH$ carbons are $sp^2$ hybridised,and the $CN$ carbon is $sp$ hybridised.
$(v)$ $C_6H_6$: All $6$ carbon atoms in the benzene ring are $sp^2$ hybridised.
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Similar Questions
Number of $sp$ hybridised carbon atoms in the given compound $CH_2=CH-C\equiv C-CH_2-CN$ is:
Medium
View SolutionThe ascending acidity order of the following $H$ atoms is:
$A: HC \equiv C-H$
$B: H_2C=CH-H$
$C: (CH_3)_3C-H$
$D: CH_3-CH_2-H$
$A: HC \equiv C-H$
$B: H_2C=CH-H$
$C: (CH_3)_3C-H$
$D: CH_3-CH_2-H$
DifficultJEE MAIN 2024
View Solution$(a)$ Discuss the concept of hybridization. What are its different types in a carbon atom.
$(b)$ What is the type of hybridization of carbon atoms marked with a star in the following structures:
$(a)$ $\overset{*}{C}H_2 = CH - C(=O)OH$
$(b)$ $CH_3 - \overset{*}{C}H_2 - OH$
$(c)$ $CH_3 - CH_2 - \overset{*}{C}H = O$
$(d)$ $\overset{*}{C}H_3 - CH = CH - CH_3$
$(e)$ $CH_3 - \overset{*}{C} \equiv CH$
$(b)$ What is the type of hybridization of carbon atoms marked with a star in the following structures:
$(a)$ $\overset{*}{C}H_2 = CH - C(=O)OH$
$(b)$ $CH_3 - \overset{*}{C}H_2 - OH$
$(c)$ $CH_3 - CH_2 - \overset{*}{C}H = O$
$(d)$ $\overset{*}{C}H_3 - CH = CH - CH_3$
$(e)$ $CH_3 - \overset{*}{C} \equiv CH$
Difficult
View SolutionWhich of the following molecules represents the order of hybridisation $sp^2, sp^2, sp, sp$ from left to right for the carbon atoms?
The compound having both $sp$ and $sp^{2}$ hybridised carbon atoms is
MediumIIT 1981
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