(A) The possible structural isomers for pentyne $(C_5H_8)$ are:$(i)$ $CH \equiv C - CH_2 - CH_2 - CH_3$ (Pent-$1$-yne)$(ii)$ $CH_3 - C \equiv C - CH_2

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(A) The possible structural isomers for pentyne $(C_5H_8)$ are:$(i)$ $CH \equiv C - CH_2 - CH_2 - CH_3$ (Pent-$1$-yne)$(ii)$ $CH_3 - C \equiv C - CH_2 - CH_3$ (Pent-$2$-yne)$(iii)$ $CH \equiv C - CH(CH_3) - CH_3$ ($3$-methylbut-$1$-yne)Thus,the total number of possible isomers is $3$.