Which of the following does not contain an sp | vedclass

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(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH

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Acetonitrile

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(C) To determine the hybridization of carbon atoms,we look at the number of sigma bonds and lone pairs attached to the carbon atom.$1$. Acetamide $(CH_3CONH_2)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$2$. Acetic acid $(CH_3COOH)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.$3$. Acetonitrile $(CH_3C \equiv N)$: The methyl carbon is $sp^3$ hybridized,and the nitrile carbon $(C \equiv N)$ is $sp$ hybridized. Thus,it contains no $sp^2$ hybridized carbon.$4$. Acetone $(CH_3COCH_3)$: The carbonyl carbon $(C=O)$ is $sp^2$ hybridized.Therefore,the correct option is $C$.

Which of the following does not contain an $sp^2$ hybridized carbon?

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