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(A) The acidic strength of nitroalkanes depends on the stability of the conjugate base (carbanion) formed after the removal of an $\alpha$-hydrogen.$1

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$IV > II > I > III$

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(A) The acidic strength of nitroalkanes depends on the stability of the conjugate base (carbanion) formed after the removal of an $\alpha$-hydrogen.$1$. The stability of the carbanion is increased by the electron-withdrawing effect ($-I$ and $-M$ effects) of the $-NO_2$ groups.$2$. Comparing the compounds:$(I) \ CH_3NO_2$ has $3 \ \alpha$-hydrogens and one $-NO_2$ group.$(II) \ (NO_2)_2CH_2$ has $2 \ \alpha$-hydrogens and two $-NO_2$ groups.$(III) \ CH_3CH_2NO_2$ has $2 \ \alpha$-hydrogens and one $-NO_2$ group (the $+I$ effect of the $-CH_3$ group destabilizes the carbanion).$(IV) \ (NO_2)_3CH$ has $1 \ \alpha$-hydrogen and three $-NO_2$ groups.$3$. The order of stability of the resulting carbanions is $(IV) > (II) > (I) > (III)$.Therefore,the correct order of acidic strength is $IV > II > I > III$.

Write the correct order of acidic strength for the following:
$(I) \ CH_3 - NO_2$
$(II) \ NO_2 - CH_2 - NO_2$
$(III) \ CH_3 - CH_2 - NO_2$
$(IV) \ (NO_2)_3CH$

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Explain the terms Inductive and Electromeric effects. Which electron displacement effect explains the following correct orders of acidity of the carboxylic acids?
$(a)$ $Cl_3CCOOH > Cl_2CHCOOH > ClCH_2COOH$
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Determine the correct order of stability for the following carbocations:

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Write the correct order of acidic strength for the following:$(I) \ CH_3 - NO_2$$(II) \ NO_2 - CH_2 - NO_2$$(III) \ CH_3 - CH_2 - NO_2$$(IV) \ (NO_2)_3CH$