The reaction of propene with HOCl proceeds vi | vedclass

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(B) The reaction of propene $(CH_3-CH=CH_2)$ with $HOCl$ (hypochlorous acid) is an electrophilic addition reaction. $HOCl$ dissociates to provide the

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First step $Cl^{+}$

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(B) The reaction of propene $(CH_3-CH=CH_2)$ with $HOCl$ (hypochlorous acid) is an electrophilic addition reaction. $HOCl$ dissociates to provide the electrophile $Cl^{+}$ and the nucleophile $OH^{-}$. In the first step,the electrophile $Cl^{+}$ attacks the double bond of propene to form a cyclic chloronium ion intermediate. Therefore,the reaction proceeds via the addition of $Cl^{+}$ in the first step.

The reaction of propene with $HOCl$ proceeds via the addition of which of the following in the first step?

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