What is the magnetic moment value of Ni^{2+} | vedclass

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(A) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.
For $Ni^{2+}$,the configuration is $[Ar] 3d^8$.
In an aqueous solution,$Ni^{2

Vedclass · Accepted Answer

$2.83$

Vedclass · Answer

(A) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.
For $Ni^{2+}$,the configuration is $[Ar] 3d^8$.
In an aqueous solution,$Ni^{2+}$ forms the complex $[Ni(H_2O)_6]^{2+}$.
In the $3d^8$ configuration,there are $2$ unpaired electrons $(n=2)$.
The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \, B.M.$
$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \, B.M.$

What is the magnetic moment value of $Ni^{2+}$ in an aqueous solution in Bohr Magnetons? (Atomic number: $Ni = 28$)

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