Which of the following complexes exhibits opt | vedclass

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(C) Optical isomerism is exhibited by complexes that lack a plane of symmetry and a center of inversion (i.e.,they are chiral).For octahedral complexe

Vedclass · Accepted Answer

$[CO(en)_3]^{3+}$

Vedclass · Answer

(C) Optical isomerism is exhibited by complexes that lack a plane of symmetry and a center of inversion (i.e.,they are chiral).For octahedral complexes of the type $[M(AA)_3]^{n+}$,where $AA$ is a bidentate ligand like ethylenediamine $(en)$,the complex exists as a pair of enantiomers (non-superimposable mirror images).In the given options,$[CO(en)_3]^{3+}$ is an octahedral complex with three bidentate ligands,which lacks a plane of symmetry and is optically active.$[Zn(en)_2]^{2+}$ is a tetrahedral complex,which generally does not show optical isomerism unless all four ligands are different.$[CO(H_2O)_4(en)]^{3+}$ is of the type $[M(AA)a_4]$,which possesses a plane of symmetry and is therefore optically inactive.

List-$I$ (Complex ion)	List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$	$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$	$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$	$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$	$IV$. $1.73$

Which of the following complexes exhibits optical isomerism?

Similar Questions

The $d-$ electron configurations of $Cr^{2+}, Mn^{2+}, Fe^{2+}$ and $Co^{2+}$ are $d^4, d^5, d^6$ and $d^7$ respectively. Which one of the following will exhibit the lowest paramagnetic behaviour? (Atomic no. $Cr = 24, Mn = 25, Fe = 26, Co = 27$).

Explain stereoisomerism in coordination compounds.

Out of the following two coordination entities,which is chiral (optically active)?
$(a)$ $cis-[CrCl_{2}(ox)_{2}]^{3-}$
$(b)$ $trans-[CrCl_{2}(ox)_{2}]^{3-}$

Consider the following complex compounds and identify the compounds which are optically active.
$I.$ $[Co(NO_2)_3(NH_3)_3]$
$II.$ $cis-[RhCl_2(NH_3)_4]^+$
$III.$ $[Cr(OX)_3]^{3-}$
$IV.$ $cis-[PtCl_2(en)]$
$V.$ $trans-[Cr(en)_2Br_2]^+$
$VI.$ $cis-[Cr(en)_2Br_2]^+$

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