The hexachloridocobaltate (III) ion is a high | vedclass

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(C) The chemical formula for the hexachloridocobaltate $(III)$ ion is $[CoCl_6]^{3-}$.In this complex,the oxidation state of $Co$ is $+3$.The electron

Vedclass · Accepted Answer

$sp^3d^2$

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(C) The chemical formula for the hexachloridocobaltate $(III)$ ion is $[CoCl_6]^{3-}$.In this complex,the oxidation state of $Co$ is $+3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Therefore,the $3d$ electrons remain unpaired,resulting in a high-spin complex.To accommodate six ligands,the $Co^{3+}$ ion uses one $4s$,three $4p$,and two $4d$ orbitals,leading to $sp^3d^2$ hybridisation.Thus,the geometry is octahedral and the hybridisation is $sp^3d^2$.

The hexachloridocobaltate $(III)$ ion is a high-spin complex. What is the possible hybridisation state of the cobalt ion in this complex?

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Select the option with the correct property -

Which one is an example of an octahedral complex?

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