Which of the following complexes is colored?

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(C) complex is colored if it contains a metal ion with an incomplete $d$-subshell,allowing for $d-d$ transitions.In $[Cr(NH_3)_5Cl]^{2+}$,the oxidatio

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$[Cr(NH_3)_5Cl]^{2+}$

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(C) complex is colored if it contains a metal ion with an incomplete $d$-subshell,allowing for $d-d$ transitions.In $[Cr(NH_3)_5Cl]^{2+}$,the oxidation state of $Cr$ is $+3$.The electronic configuration of $Cr^{3+}$ is $[Ar] 3d^3$.Since it has unpaired electrons in the $d$-orbitals,it undergoes $d-d$ transitions and exhibits color.$Ti(NO_3)_4$ contains $Ti^{4+}$ $(3d^0)$,$[Cu(NCCH_3)_4]^{+}$ contains $Cu^{+}$ $(3d^{10})$,and $Li[AlH_4]$ contains $Al^{3+}$ $(3d^0)$,all of which are colorless due to the absence of $d-d$ transitions.

List $I$ (Complex)	List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$	$I$. Optical
$B$. $[Co(en)_3]^{3+}$	$II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$	$III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$	$IV$. Linkage

Compound	Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$	$P$. $2$
$B$. $[Co(en)_3]Cl_3$	$Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$	$R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$	$S$. $5$

Similar Questions

Number of possible isomers for $[Cr(H_2O)_2(C_2O_4)_2]^{-}$ are . . . . . . .

Match List $I$ with List $II$ :
List $I$ (Complex) List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$ $I$. Optical
$B$. $[Co(en)_3]^{3+}$ $II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$ $III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$ $IV$. Linkage

Choose the correct answer from the options given below :

The total number of possible isomers for the complex compound $[Cu^{II}(NH_3)_4][Pt^{II}Cl_4]$ are

If the spin-only magnetic moment of $VCl_x$ is $1.73 \ BM$,then the correct formula is:

Compound Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$ $P$. $2$
$B$. $[Co(en)_3]Cl_3$ $Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$ $R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$ $S$. $5$

Match the compounds with their total number of stereoisomers and select the correct code:

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