Find the equation of the chord of contact of the tangents drawn from the point $(2, -3)$ to the circle $x^2 + y^2 + 4x - 6y - 12 = 0$.

  • A
    $x - 2y + 4 = 0$
  • B
    $2x - 3y + 4 = 0$
  • C
    $2x + 4y + 3 = 0$
  • D
    $4x - 6y + 1 = 0$

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If the chord of contact of the point $P(1, 1)$ with respect to the circle $S = x^2 + y^2 + 4x + 6y - 3 = 0$ meets the circle $S = 0$ at $A$ and $B$,then the area of $\triangle PAB$ is

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