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(A) The given equations of the circles are:$S_1: x^2 + y^2 - x + 1 = 0$$S_2: 3(x^2 + y^2) + y - 1 = 0$To find the radical axis,we first normalize the

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$3x + y - 4 = 0$

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(A) The given equations of the circles are:$S_1: x^2 + y^2 - x + 1 = 0$$S_2: 3(x^2 + y^2) + y - 1 = 0$To find the radical axis,we first normalize the equations so that the coefficients of $x^2$ and $y^2$ are the same.Multiply $S_1$ by $3$:$3x^2 + 3y^2 - 3x + 3 = 0$Now,subtract the second equation from the first:$(3x^2 + 3y^2 - 3x + 3) - (3x^2 + 3y^2 + y - 1) = 0$$-3x - y + 3 + 1 = 0$$-3x - y + 4 = 0$Multiplying by $-1$,we get:$3x + y - 4 = 0$

Find the equation of the radical axis of the two circles $x^2 + y^2 - x + 1 = 0$ and $3(x^2 + y^2) + y - 1 = 0$.

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