If the circles $x^2 + y^2 + 2x + 2ky + 6 = 0$ and $x^2 + y^2 + 2ky + k = 0$ intersect orthogonally,then $k = ..........$

  • A
    $2$ or $-3/2$
  • B
    $-2$ or $-3/2$
  • C
    $2$ or $3/2$
  • D
    $-2$ or $3/2$

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