Find the equation of the latus rectum of the | vedclass

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(C) The given equation of the parabola is $x^2 = -12y$.Comparing this with the standard form $x^2 = -4ay$,we get $4a = 12$,which implies $a = 3$.The f

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$y = -3$

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(C) The given equation of the parabola is $x^2 = -12y$.Comparing this with the standard form $x^2 = -4ay$,we get $4a = 12$,which implies $a = 3$.The focus of this parabola is $(0, -a) = (0, -3)$.The latus rectum is a line passing through the focus and perpendicular to the axis of the parabola.Since the axis of the parabola is the $y$-axis,the latus rectum is a horizontal line given by $y = -a$.Therefore,the equation of the latus rectum is $y = -3$.

Find the equation of the latus rectum of the parabola $x^2 = -12y$.

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