The vertices of a triangle are A(4, -2),B(2, | vedclass

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Question

(A) The median from $C$ passes through $C(5, -4)$ and the midpoint $D$ of $AB$.The coordinates of $D$ are $\left( \frac{4+2}{2}, \frac{-2+3}{2} \right

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$9x + 4y - 29 = 0$

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(A) The median from $C$ passes through $C(5, -4)$ and the midpoint $D$ of $AB$.The coordinates of $D$ are $\left( \frac{4+2}{2}, \frac{-2+3}{2} \right) = \left( 3, \frac{1}{2} \right)$.The equation of the line passing through $C(5, -4)$ and $D(3, 1/2)$ is given by the two-point form:$y - (-4) = \frac{\frac{1}{2} - (-4)}{3 - 5} (x - 5)$$y + 4 = \frac{4.5}{-2} (x - 5)$$y + 4 = -2.25 (x - 5)$$y + 4 = -\frac{9}{4} (x - 5)$$4(y + 4) = -9(x - 5)$$4y + 16 = -9x + 45$$9x + 4y - 29 = 0$.

The vertices of a triangle are $A(4, -2)$,$B(2, 3)$,and $C(5, -4)$. Find the equation of the median drawn from $C$.

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