If a ray travels along the line x = 1 and get | vedclass

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Question

(A) The incident ray is along the line $x = 1$,which is a vertical line. The reflecting line is $x + y = 1$,which has a slope of $-1$ (making an angle

Vedclass · Accepted Answer

$y = 0$

Vedclass · Answer

(A) The incident ray is along the line $x = 1$,which is a vertical line. The reflecting line is $x + y = 1$,which has a slope of $-1$ (making an angle of $135^{\circ}$ with the positive $x$-axis).The angle between the incident ray ($x = 1$,slope $m_1 = \infty$) and the reflecting line ($x + y = 1$,slope $m_2 = -1$) is $45^{\circ}$.By the law of reflection,the angle of incidence equals the angle of reflection. The reflected ray must make an angle of $45^{\circ}$ with the reflecting line.Since the incident ray is vertical,the reflected ray must be horizontal. $A$ horizontal line has a slope of $m = 0$.The point of intersection of $x = 1$ and $x + y = 1$ is $(1, 0)$.The equation of the reflected ray passing through $(1, 0)$ with slope $m = 0$ is $y - 0 = 0(x - 1)$,which simplifies to $y = 0$.

If a ray travels along the line $x = 1$ and gets reflected by the line $x + y = 1$,find the equation of the reflected ray.

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