If 16a^2 - 40ab + 25b^2 - c^2 = 0,then the li | vedclass

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(A) Given equation is $16a^2 - 40ab + 25b^2 - c^2 = 0$. This can be written as $(4a - 5b)^2 - c^2 = 0$. Using the identity $x^2 - y^2 = (x - y)(x + y)

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$(4, -5)$ and $(-4, 5)$

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(A) Given equation is $16a^2 - 40ab + 25b^2 - c^2 = 0$. This can be written as $(4a - 5b)^2 - c^2 = 0$. Using the identity $x^2 - y^2 = (x - y)(x + y)$,we get $(4a - 5b - c)(4a - 5b + c) = 0$. This implies $4a - 5b - c = 0$ or $4a - 5b + c = 0$. We compare these with the line equation $ax + by + c = 0$. Case $1$: $4a - 5b + c = 0$ can be written as $a(4) + b(-5) + c = 0$. Comparing with $ax + by + c = 0$,we get $(x, y) = (4, -5)$. Case $2$: $4a - 5b - c = 0$ can be written as $a(-4) + b(5) + c = 0$. Comparing with $ax + by + c = 0$,we get $(x, y) = (-4, 5)$. Thus,the line passes through $(4, -5)$ and $(-4, 5)$.

If $16a^2 - 40ab + 25b^2 - c^2 = 0$,then the line $ax + by + c = 0$ passes through which points?

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