If the line passing through the points (4, 3) | vedclass

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(A) Let the slope of the line passing through $(4, 3)$ and $(2, \lambda)$ be $m_1$. $m_1 = \frac{\lambda - 3}{2 - 4} = \frac{\lambda - 3}{-2}$. The gi

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$4$

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(A) Let the slope of the line passing through $(4, 3)$ and $(2, \lambda)$ be $m_1$. $m_1 = \frac{\lambda - 3}{2 - 4} = \frac{\lambda - 3}{-2}$. The given line is $y = 2x + 3$,which is in the form $y = mx + c$. So,the slope of this line is $m_2 = 2$. Since the two lines are perpendicular,the product of their slopes must be $-1$: $m_1 	imes m_2 = -1$. $\left(\frac{\lambda - 3}{-2}ight) 	imes 2 = -1$. $-(\lambda - 3) = -1$. $\lambda - 3 = 1$. $\lambda = 4$.

If the line passing through the points $(4, 3)$ and $(2, \lambda)$ is perpendicular to the line $y = 2x + 3$,then find the value of $\lambda$.

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