Find the length of the latus rectum of the el | vedclass

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(B) The given equation of the ellipse is $\frac{x^2}{36} + \frac{y^2}{49} = 1$.Comparing this with the standard form $\frac{x^2}{b^2} + \frac{y^2}{a^2

Vedclass · Accepted Answer

$72/7$

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(B) The given equation of the ellipse is $\frac{x^2}{36} + \frac{y^2}{49} = 1$.Comparing this with the standard form $\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1$,where $a^2 > b^2$,we have $a^2 = 49$ and $b^2 = 36$.Here,$a = 7$ and $b = 6$.The major axis is along the $y$-axis.The length of the latus rectum of an ellipse is given by the formula $\frac{2b^2}{a}$.Substituting the values,we get $	ext{Length} = \frac{2 	imes 36}{7} = \frac{72}{7}$.

Find the length of the latus rectum of the ellipse $\frac{x^2}{36} + \frac{y^2}{49} = 1$.

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