If one end of a diameter of the circle $x^2 + y^2 + 2x + 4y - 3 = 0$ is $(1, 0)$,then the other end of the diameter is:

  • A
    $(-3, -4)$
  • B
    $(-3, 4)$
  • C
    $(3, -4)$
  • D
    $(3, 4)$

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