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(A) Step $1$: Find the intersection point of the lines $y = 3$ and $x + y = 0$.Substituting $y = 3$ into $x + y = 0$,we get $x + 3 = 0$,which implies

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$2x - y + 9 = 0$

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(A) Step $1$: Find the intersection point of the lines $y = 3$ and $x + y = 0$.Substituting $y = 3$ into $x + y = 0$,we get $x + 3 = 0$,which implies $x = -3$.So,the intersection point is $(-3, 3)$.Step $2$: Find the equation of a line parallel to $2x - y = 4$.$A$ line parallel to $2x - y = 4$ is of the form $2x - y + k = 0$.Step $3$: Substitute the point $(-3, 3)$ into the equation $2x - y + k = 0$ to find $k$.$2(-3) - (3) + k = 0$$-6 - 3 + k = 0$$-9 + k = 0$,which gives $k = 9$.Step $4$: The required equation is $2x - y + 9 = 0$.

Find the equation of the line passing through the intersection of the lines $y = 3$ and $x + y = 0$ and parallel to the line $2x - y = 4$.

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