The maximum value of $f(x) = \frac{1}{4x^2 + 2x + 1}$ is .....

  • A
    $4/3$
  • B
    $2/3$
  • C
    $1$
  • D
    $3/4$

Explore More

Similar Questions

Local maximum value of the function $\frac{\log x}{x}$ is

Let $R$ denote the set of all real numbers. Let $f: R \rightarrow R$ be defined by $f(x)=\begin{cases} \frac{6x+\sin x}{2x+\sin x} & \text{if } x \neq 0 \\ \frac{7}{3} & \text{if } x=0 \end{cases}$. Then which of the following statements is (are) True?
$(A)$ The point $x=0$ is a point of local maxima of $f$
$(B)$ The point $x=0$ is a point of local minima of $f$
$(C)$ Number of points of local maxima of $f$ in the interval $[\pi, 6\pi]$ is $3$
$(D)$ Number of points of local minima of $f$ in the interval $[2\pi, 4\pi]$ is $1$

For the function $f(x) = x^4(12\ln x - 7)$,match the following columns:
Column-$I$ Column-$II$
$(A)$ If $(a, b)$ is a point of inflection,then $a - b$ equals $(P)$ $3$
$(B)$ If $e^t$ is the point of local minimum,then $12t$ equals $(Q)$ $1$
$(C)$ If the graph is concave down on $(d, e)$,then $d + 3e$ equals $(R)$ $4$
$(D)$ If the graph is concave up on $(p, \infty)$,then $p$ equals $(S)$ $8$

Difficult
View Solution

The perimeter of a sector is $p$. The area of the sector is maximum when its radius is

If $S_1$ and $S_2$ are respectively the sets of local minimum and local maximum points of the function $f(x) = 9x^4 + 12x^3 - 36x^2 + 25, x \in R$,then

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo