(C) Given,velocity $v = 1.0t$ and radius $r = 0.1 \ m$. Tangential acceleration $a_t = \frac{dv}{dt} = \frac{d}{dt}(1.0t) = 1.0 \ m/s^2$. At $t = 5 \

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(C) Given,velocity $v = 1.0t$ and radius $r = 0.1 \ m$. Tangential acceleration $a_t = \frac{dv}{dt} = \frac{d}{dt}(1.0t) = 1.0 \ m/s^2$. At $t = 5 \ s$,the velocity $v = 1.0 \times 5 = 5 \ m/s$. Centripetal acceleration $a_c = \frac{v^2}{r} = \frac{5^2}{0.1} = \frac{25}{0.1} = 250 \ m/s^2$. The total acceleration $a_{net} = \sqrt{a_c^2 + a_t^2} = \sqrt{250^2 + 1^2} = \sqrt{62500 + 1} = \sqrt{62501} \approx 250 \ m/s^2$.

Class 11 Physics 3-2.Motion in Plane Non-uniform Circular Motion (Centrifugal/Centripetal and tangential Accelaration)

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$A$ particle moves on a circle of radius $0.1 \ m$ with a velocity $v = 1.0t$. The total acceleration at $t = 5 \ s$ will be ........ $m/s^2$.

A
$10$
B
$100$
C
$250$
D
$500$

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3-2.Motion in Plane

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Non-uniform Circular Motion (Centrifugal/Centripetal and tangential Accelaration)

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For a particle in circular motion,the centripetal acceleration is

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$A$ particle moves on a circle of radius $0.1 \ m$ with a velocity $v = 1.0t$. The total acceleration at $t = 5 \ s$ will be ........ $m/s^2$.

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What happens to the centripetal acceleration of a revolving body if you double the orbital speed $v$ and halve the angular velocity $\omega$?

$A$ particle moves along a circle of radius $3 \, m$ with its displacement given by $S = \frac{t^2}{2} + \frac{t^3}{3}$. The total acceleration at $t = 2 \, s$ is ....... $m/s^2$.

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