What is the acceleration of the particle on O | vedclass

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Question

(A) The acceleration is given by the slope of the velocity-time graph.For segment $OA$: Acceleration $a_{OA} = \frac{v_A - v_O}{t_A - t_O} = \frac{10

Vedclass · Accepted Answer

$1, 0, -0.5$

Vedclass · Answer

(A) The acceleration is given by the slope of the velocity-time graph.For segment $OA$: Acceleration $a_{OA} = \frac{v_A - v_O}{t_A - t_O} = \frac{10 - 0}{10 - 0} = 1 \ m/s^2$.For segment $AB$: Since velocity is constant,acceleration $a_{AB} = 0 \ m/s^2$.For segment $BC$: Acceleration $a_{BC} = \frac{v_C - v_B}{t_C - t_B} = \frac{0 - 10}{40 - 20} = \frac{-10}{20} = -0.5 \ m/s^2$.Thus,the accelerations are $1, 0, -0.5$.

What is the acceleration of the particle on $OA$,$AB$,and $BC$ respectively?

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