(B) For the system to move with a constant velocity,the net force on the system must be zero. This means the tension in the string must balance the fr

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(B) For the system to move with a constant velocity,the net force on the system must be zero. This means the tension in the string must balance the frictional force on the block ${M_1}$ and the weight of the block ${M_2}$.The frictional force $f$ acting on the combined mass $(M_1 + m)$ is given by $f = \mu N = \mu (M_1 + m)g$.The tension $T$ in the string is equal to the weight of the hanging block,$T = M_2 g$.For constant velocity,$T = f$,so:$M_2 g = \mu (M_1 + m)g$$M_2 = \mu (M_1 + m)$$\frac{M_2}{\mu} = M_1 + m$$m = \frac{M_2}{\mu} - M_1$

Class 11 Physics Newton's Laws of Motion and Friction Kinetic Friction and Motion on Rough Horizontal Surface

Medium

The coefficient of friction between the block of mass ${M_1}$ and the surface is $\mu$. When the system is released,it moves with acceleration. What mass $m$ should be placed on the block ${M_1}$ so that the system moves with a constant velocity?

A
$\frac{{{M_2 - M_1}}}{\mu }$
B
$\frac{{{M_2}}}{\mu } - {M_1}$
C
${M_2} - \frac{{{M_1}}}{\mu }$
D
$({M_2} - {M_1})\mu $

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Class 11

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Chapter

Newton's Laws of Motion and Friction

Subtopic

Kinetic Friction and Motion on Rough Horizontal Surface

$A$ block of mass $40 \,kg$ slides over a surface,when a mass of $4 \,kg$ is suspended through an inextensible massless string passing over a frictionless pulley as shown below. The coefficient of kinetic friction between the surface and the block is $0.02$. The acceleration of the block is ............ $m/s^2$. (Given $g = 10 \,m/s^2$.)

MediumJEE MAIN 2022

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$A$ body is pulled along a rough horizontal surface with a velocity $6\,m/s$. If the body comes to rest after travelling $9\,m$,then the coefficient of sliding friction is- (Take $g = 10\,m/s^2$)

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$A$ force $F$ pulls a block of mass $60 \ kg$ at a constant speed across the floor. The coefficient of friction is $\mu = 1/3$. What is the magnitude of the force $F$ (in $N$)?

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$A$ wooden block of mass $m$ resting on a rough surface (coefficient of friction $\mu$) is pulled by a force $F$ at an angle $\theta$ with the horizontal,as shown in the figure. The acceleration of the block moving horizontally is:

Difficult

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$A$ body of mass $m$ moves with a velocity $v$ on a surface whose friction coefficient is $\mu$. If the body covers a distance $s$ before coming to rest,what is the initial velocity $v$?

Medium

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The coefficient of friction between the block of mass ${M_1}$ and the surface is $\mu$. When the system is released,it moves with acceleration. What mass $m$ should be placed on the block ${M_1}$ so that the system moves with a constant velocity?

Similar Questions

$A$ body is pulled along a rough horizontal surface with a velocity $6\,m/s$. If the body comes to rest after travelling $9\,m$,then the coefficient of sliding friction is- (Take $g = 10\,m/s^2$)

$A$ force $F$ pulls a block of mass $60 \ kg$ at a constant speed across the floor. The coefficient of friction is $\mu = 1/3$. What is the magnitude of the force $F$ (in $N$)?

$A$ wooden block of mass $m$ resting on a rough surface (coefficient of friction $\mu$) is pulled by a force $F$ at an angle $\theta$ with the horizontal,as shown in the figure. The acceleration of the block moving horizontally is:

$A$ body of mass $m$ moves with a velocity $v$ on a surface whose friction coefficient is $\mu$. If the body covers a distance $s$ before coming to rest,what is the initial velocity $v$?

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