A capillary tube of length l and radius r is | vedclass

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(B) According to Poiseuille's law,the volume flow rate $V$ is given by $V = \frac{P}{R}$,where $R$ is the fluid resistance.Resistance $R$ is given by

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$\frac{V}{17}$

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(B) According to Poiseuille's law,the volume flow rate $V$ is given by $V = \frac{P}{R}$,where $R$ is the fluid resistance.Resistance $R$ is given by $R = \frac{8\eta l}{\pi r^4}$.For the first tube,$R = \frac{8\eta l}{\pi r^4}$.For the second tube with radius $r' = \frac{r}{2}$,the resistance $R'$ is:$R' = \frac{8\eta l}{\pi (r/2)^4} = \frac{8\eta l}{\pi r^4} 	imes 16 = 16R$.When connected in series,the total resistance $R_{total} = R + R' = R + 16R = 17R$.The new volume flow rate $V_{new}$ is:$V_{new} = \frac{P}{R_{total}} = \frac{P}{17R} = \frac{V}{17}$.

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