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(C) Since no work is done in the process,the process is isochoric (constant volume).For an isochoric process,the heat supplied is equal to the change

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(C) Since no work is done in the process,the process is isochoric (constant volume).For an isochoric process,the heat supplied is equal to the change in internal energy: $\Delta Q = \Delta U$.The formula for internal energy change is $\Delta U = n \, C_v \, \Delta T$.For a monoatomic gas,the molar heat capacity at constant volume is $C_v = \frac{3}{2} R$.Given: $n = 2 \ moles$,$\Delta T = 373 \ K - 273 \ K = 100 \ K$.Substituting the values: $\Delta Q = 2 	imes \frac{3}{2} R 	imes 100 = 300 \ R$.

Find the heat energy required to increase the temperature of $2$ moles of a monoatomic gas from $273 \ K$ to $373 \ K$. (No work is done in the process.) (in $R$)

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