$A$ wall consists of two layers $A$ and $B$ of equal thickness. Their thermal resistances are $R_1$ and $R_2$. Find the temperature of the interface.

  • A
    $\frac{\theta_1 + \theta_2}{2}$
  • B
    $\frac{R_1\theta_2 + R_2\theta_1}{R_1 + R_2}$
  • C
    $\frac{R_1\theta_1 + R_2\theta_2}{R_1 + R_2}$
  • D
    $\frac{R_2\theta_1 + R_1\theta_2}{\theta_1 + \theta_2}$

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