$A$ wave with a frequency of $100 \, Hz$ has a velocity of $10 \, m/s$. What is the phase difference between two particles separated by a distance of $2.5 \, cm$?

$A$ traveling wave is described by the equation $y(x,t) = [0.05 \sin(8x - 4t)] \text{ m}$. The velocity of the wave is (All the quantities are in $SI$ units). (in $\text{ m/s}$)

The maximum particle velocity in a wave motion is half the wave velocity. Then the amplitude of the wave is equal to

The displacement of a wave travelling in the $x$ direction is $y = 10^{-4} \sin(600t - 2x + \pi/3) \text{ m}$,where $x$ is in metres and $t$ is in seconds. The speed of the wave is: (in $\text{ m/s}$)

The transverse displacement $y(x, t)$ of a wave on a string is given by $y(x, t) = e^{-(ax^2 + bt^2 + 2\sqrt{ab}xt)}$. This represents a:

$A$ sinusoidal wave of wavelength $7.5 \ cm$ travels a distance of $1.2 \ cm$ along the $x$-direction in $0.3 \ s$. The crest $P$ is at $x = 0$ at $t = 0 \ s$ and the maximum displacement of the wave is $2 \ cm$. Which equation correctly represents this wave?