How many sec are required to raise the temper | vedclass

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(B) The heat energy required to raise the temperature of water is given by $Q = mc\Delta	heta$.Here,mass $m = 1\, kg$ (since $1\, litre$ of water has

Vedclass · Accepted Answer

$100$

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(B) The heat energy required to raise the temperature of water is given by $Q = mc\Delta	heta$.Here,mass $m = 1\, kg$ (since $1\, litre$ of water has a mass of $1\, kg$),specific heat capacity $c = 4180\, J/(kg\cdot ^oC)$,and change in temperature $\Delta	heta = 40\, ^oC - 20\, ^oC = 20\, ^oC$.So,$Q = 1 	imes 4180 	imes 20 = 83600\, J$.The power of the heater is $P = 836\, W$.The time $t$ required is given by $t = \frac{Q}{P}$.$t = \frac{83600}{836} = 100\, sec$.

How many $sec$ are required to raise the temperature of $1\, litre$ of water from $20\,^oC$ to $40\,^oC$ using an $836\, W$ heater?

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