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(D) Let the resistance of each resistor be $R$ and the applied voltage be $V$.When $n$ identical resistors are connected in series,the equivalent resi

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$90$

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(D) Let the resistance of each resistor be $R$ and the applied voltage be $V$.When $n$ identical resistors are connected in series,the equivalent resistance is $R_s = nR$.The power consumed in series is $P_s = \frac{V^2}{R_s} = \frac{V^2}{nR} = \frac{P}{n}$,where $P$ is the power of a single resistor.Given $P_s = 10 \, W$ and $n = 3$,we have $10 = \frac{P}{3}$,so $P = 30 \, W$.When connected in parallel,the equivalent resistance is $R_p = \frac{R}{n}$.The power consumed in parallel is $P_p = \frac{V^2}{R_p} = \frac{V^2}{R/n} = n 	imes \frac{V^2}{R} = n 	imes P$.Substituting the values,$P_p = 3 	imes 30 = 90 \, W$.

Three identical resistors are connected in series,and the total power consumed is $10 \, W$. If they are connected in parallel,what will be the total power consumed in $W$?

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