A galvanometer coil has 100 turns and an area | vedclass

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(D) The current sensitivity $(S_i)$ of a galvanometer is given by the formula: $S_i = \frac{	heta}{i} = \frac{NBA}{k}$,where $N$ is the number of tur

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$5 	imes 10^6 \, rad/A$

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(D) The current sensitivity $(S_i)$ of a galvanometer is given by the formula: $S_i = \frac{	heta}{i} = \frac{NBA}{k}$,where $N$ is the number of turns,$B$ is the magnetic field,$A$ is the area,and $k$ is the restoring torque constant.Given: $N = 100$,$A = 1 \, cm^2 = 10^{-4} \, m^2$,$B = 5 \, T$,and $k = 10^{-8} \, N-m/rad$.Substituting the values:$S_i = \frac{100 	imes 5 	imes 10^{-4}}{10^{-8}}$$S_i = \frac{500 	imes 10^{-4}}{10^{-8}} = 500 	imes 10^4 = 5 	imes 10^6 \, rad/A$.Since $1 \, A = 10^6 \, \mu A$,the sensitivity is $5 \, rad/\mu A$.

$A$ galvanometer coil has $100$ turns and an area of $1 \, cm^2$. The restoring torque constant of the coil is $10^{-8} \, N-m/rad$. If the magnetic field is $5 \, T$,what is the current sensitivity?

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