$A$ substance has a mass of $0.075 \, kg$ and a density of $7500 \, kg/m^3$. If its magnetic dipole moment is $8 \times 10^{-7} \, A \cdot m^2$,what is its magnetization in $A/m$?

The unit for molar susceptibility is

The magnetic moment produced in a substance of mass $5 \ g$ is $6 \times 10^{-7} \ A \cdot m^{2}$. If its density is $5 \ g/cm^{3}$,then the intensity of magnetization in $A/m$ will be:

If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$

The magnetic induction and magnetising field intensity in a sample of magnetic material are $B$ and $H$ respectively. The magnetic susceptibility of the material is

What are the dimensions of $\chi$,the magnetic susceptibility? Consider an $H$-atom. Guess an expression for $\chi$,up to a constant,by constructing a quantity of dimensions of $\chi$ out of parameters of the atom: $e, m, v, R$ and $\mu_0$. Here,$m$ is the electronic mass,$v$ is electronic velocity,$R$ is Bohr radius. Estimate the number so obtained and compare with the value of $|\chi| \approx 10^{-5}$ for many solid materials.