Find the refractive index of glass from the g | vedclass

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(B) Applying Snell's Law at the glass-water interface:$_g\mu_w = \frac{\sin i}{\sin r} \implies \frac{\mu_w}{\mu_g} = \frac{\sin i}{\sin r} \implies \

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$1/ \sin(i)$

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(B) Applying Snell's Law at the glass-water interface:$_g\mu_w = \frac{\sin i}{\sin r} \implies \frac{\mu_w}{\mu_g} = \frac{\sin i}{\sin r} \implies \mu_g = \mu_w \frac{\sin r}{\sin i} \dots (1)$Applying Snell's Law at the water-air interface (since the ray grazes the surface,the angle of refraction is $90^\circ$):$_w\mu_a = \frac{\sin r}{\sin 90^\circ} \implies \frac{1}{\mu_w} = \sin r \dots (2)$Substituting $\sin r = 1/\mu_w$ from equation $(2)$ into equation $(1)$:$\mu_g = \mu_w \cdot \frac{1/\mu_w}{\sin i} = \frac{1}{\sin i}$

Find the refractive index of glass from the given figure,where the refractive index of water is $\mu_w = 4/3$.

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