The angle of deviation for a ray passing through the given prism is $30^o$. If one half of the prism is removed,what will be the new angle of deviation in degrees?

It was found that the refractive index of the material of a certain prism varied as $\mu = 1.5 + 0.004 / \lambda^{2}$,where $\lambda$ is the wavelength of light used to measure the refractive index. The same material was then used to construct a thin prism of apex angle $10^{\circ}$. Angles of minimum deviation $\delta_{m}$ of the prism were recorded for the sources with wavelengths $\lambda_{1}$ and $\lambda_{2}$,respectively. Then,

At the condition of minimum deviation,the angle of emergence is .......

$A$ prism has a refracting angle of $30^\circ$ and a refractive index of $\sqrt{2}$. One of its faces is silvered. At what angle of incidence $i$ should a ray be incident on the other face so that it retraces its path after reflection from the silvered face?

$A$ prism with refractive index $\mu = 1.5$ has a prism angle of $30^\circ$. If a ray is incident normally on one surface,calculate its deviation. (Given: $\sin(48^\circ 36') = 0.75$)

For a prism with refractive index $\mu = 1.5$,the angle of minimum deviation is equal to the angle of incidence. Find the prism angle $A$ in degrees. (Given: $\cos 41^o = 0.75$)