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(C) The energy of the photon is given by $E = 14.4 \, keV = 14.4 	imes 10^3 	imes 1.6 	imes 10^{-19} \, J$.Using the relation $\lambda = \frac{hc}{

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$X$-rays

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(C) The energy of the photon is given by $E = 14.4 \, keV = 14.4 	imes 10^3 	imes 1.6 	imes 10^{-19} \, J$.Using the relation $\lambda = \frac{hc}{E}$,where $h = 6.63 	imes 10^{-34} \, J \cdot s$ and $c = 3 	imes 10^8 \, m/s$:$\lambda = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{14.4 	imes 10^3 	imes 1.6 	imes 10^{-19}} \approx 0.86 	imes 10^{-10} \, m = 0.86 \, \mathring{A}$.Since the wavelength is in the range of $0.01 \, \mathring{A}$ to $100 \, \mathring{A}$,this electromagnetic wave belongs to the $X$-ray region.

If the energy of an electromagnetic wave is $14.4 \, keV$,which region of the electromagnetic spectrum does it belong to?

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