C_6H_5CHO + HCN rightarrow C_6H_5CH(OH)CN. Th | vedclass

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Question

(A) The reaction of benzaldehyde $(C_6H_5CHO)$ with $HCN$ produces benzaldehyde cyanohydrin $(C_6H_5CH(OH)CN)$.In this molecule,the carbon atom attach

Vedclass · Accepted Answer

$A$ racemic mixture

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(A) The reaction of benzaldehyde $(C_6H_5CHO)$ with $HCN$ produces benzaldehyde cyanohydrin $(C_6H_5CH(OH)CN)$.In this molecule,the carbon atom attached to the $-OH$,$-CN$,$-C_6H_5$,and $-H$ groups is a chiral center.Since the starting material is achiral and the nucleophilic attack by $CN^-$ can occur from either side of the planar carbonyl group with equal probability,both enantiomers ($R$ and $S$) are formed in equal amounts.Therefore,the resulting product is a racemic mixture.

Column-$I$ (Reactants)	Column-$II$ (Major Product)
$A$. $HCHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$i$. $C_6H_5CHOHCH_3$
$B$. $C_6H_5CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$ii$. $(CH_3)_3COH$
$C$. $CH_3COCH_3 \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iii$. $CH_3CHOHCH_3$
$D$. $CH_3CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iv$. $CH_3CH_2OH$

$C_6H_5CHO + HCN \rightarrow C_6H_5CH(OH)CN$. The product formed is:

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