C and Si both have the same lattice structure | vedclass

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Question

(C) The electronic configuration of carbon $(^{6}C)$ is $1s^{2} 2s^{2} 2p^{2}$.The electronic configuration of silicon $(_{14}Si)$ is $1s^{2} 2s^{2} 2

Vedclass · Accepted Answer

The four bonding electrons in the case of $C$ lie in the second orbit,whereas in the case of $Si$ they lie in the third.

Vedclass · Answer

(C) The electronic configuration of carbon $(^{6}C)$ is $1s^{2} 2s^{2} 2p^{2}$.The electronic configuration of silicon $(_{14}Si)$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{2}$.In $C$,the valence electrons are in the $n=2$ shell,which is closer to the nucleus,resulting in a large energy band gap $(E_{g} \approx 5.4 \ eV)$,making it an insulator.In $Si$,the valence electrons are in the $n=3$ shell,which is further from the nucleus,resulting in a smaller energy band gap $(E_{g} \approx 1.1 \ eV)$,allowing it to act as an intrinsic semiconductor.Therefore,the four bonding electrons of $C$ and $Si$ lie in the second and third orbits,respectively.

$C$ and $Si$ both have the same lattice structure,having $4$ bonding electrons in each. However,$C$ is an insulator whereas $Si$ is an intrinsic semiconductor. This is because:

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